2D Trigonometry
Area of a triangle and multi-step problems
In this note
- 6.3Use area = ½ab sin C for any triangle.
- 6.3Work backwards from an area to a side or an angle.
- 6.3Solve multi-step problems: split shapes into triangles and chain the rules.
Before you start: The sine and cosine rules.
Formula bank
Area = ½ab sin C
'Half base times height' needs the height. The trig formula finds it for you: with sides a and b and the angle C between them, the height is \(b\sin C\), so the area is \(\tfrac12ab\sin C\).
General methodHow to find the area of any triangle
- Find two sides and the angle BETWEEN them.
- Not between? Use the sine or cosine rule first to get the right angle or side.
- Area \(=\tfrac12ab\sin C\).
Example Two sides are 8 cm and 11 cm with 40° between them. Find the area.
Two sides and the included angle.
- \(\tfrac12(8)(11)\sin40^\circ=28.28\)
Answer 28.3 cm²
Example A triangle has sides 8 cm and 10 cm and area 30 cm². Find the angle between those sides.
Work backwards.
- \(\tfrac12(8)(10)\sin C=30\)
- \(\sin C=0.75\)
- \(C=48.6^\circ\) or \(180^\circ-48.6^\circ=131.4^\circ\)
Answer 48.6° (or 131.4° if the angle is obtuse)
Try it yourself
Show answer
Answer 11.49
Hint
Show answer
Answer 10.05
Multi-step problems
Exam questions chain the rules. Split the shape into triangles, find the shared side (often a diagonal) in the first triangle, then use it in the second.
General methodHow to answer a multi-step triangle question
- Split the shape into triangles; mark everything you know.
- Find a triangle where you can already use a rule. Work out the missing piece (often the shared side).
- Carry it, unrounded, into the next triangle.
- Areas of a quadrilateral: add the two triangles.
Example ABCD: AB = 6, AD = 8, angle BAD = 70°, BC = 5, CD = 7 (cm). Find the area of ABCD.
Triangle ABD first (SAS), then BCD needs its angle at C.
- area ABD \(=\tfrac12(6)(8)\sin70^\circ=22.55\)
- \(BD^{2}=36+64-96\cos70^\circ=67.17\)
- \(\cos C=\dfrac{25+49-67.17}{70}\Rightarrow C=84.4^\circ\)
- area BCD \(=\tfrac12(5)(7)\sin84.4^\circ=17.42\)
- total \(=39.97\)
Answer 40.0 cm²
Ways they test it
Type 1 Area directly
"Calculate the area of triangle ABC." (2 marks)
Spot it two sides and the angle between.
- \(\tfrac12ab\sin C\).
Type 2 Area needs a first step
"Calculate the area." (5 marks)
Spot it the known angle is NOT between the known sides.
- Sine/cosine rule for the missing piece.
- Then the area.
Type 3 Area given
"The area is 30 cm². Find angle C." (3 marks)
Spot it an area in the question.
- Area formula = value.
- \(\sin^{-1}\); obtuse? 180 − it.
For example Sides 8, 10, area 30
- \(\sin C=0.75\)
Answer 48.6°
Type 4 Field / quadrilateral
"ABCD is a field... Calculate its area." (6-10 marks)
Spot it a 4-sided shape with a diagonal.
- Two triangles; shared diagonal.
- Add the areas.
Mistakes to avoid
- ✗ Using an angle that is not between the two sides✓ find the included angle first
- ✗ Rounding the diagonal before the second triangle✓ keep it on the calculator (ANS)Early rounding loses the accuracy mark.
- ✗ Forgetting the ½✓ \(\tfrac12ab\sin C\)
Summary
- Area \(=\tfrac12ab\sin C\), C between a and b.
- Area given? Rearrange; an angle could be acute or obtuse.
- Big shapes: split into triangles, chain the rules, keep full accuracy.
If you see …
- 'area of triangle' with no height\(\tfrac12ab\sin C\).
- a quadrilateralsplit along a diagonal.
Practice
Practice: easy, medium, hard
Easy
Show answer
Answer 28.28
Show answer
Answer 23.41
Hint
Show answer
Answer 62.35
Medium
Guide me
What is it asking? an angle
What do we know? \(40\sin C=30\)
Plan \(\sin^{-1}0.75\)
Show working
- 48.6
Answer 48.6
Guide me
What is it asking? an angle
What do we know? acute 48.6°
Plan 180 − 48.6
Show working
- 131.4
Answer 131.4
Guide me
What is it asking? a side
What do we know? \(6a\sin56^\circ=50\)
Plan \(a=50\div(6\sin56^\circ)\)
Show working
- 10.05
Answer 10.05
Hard
Guide me
What is it asking? a side
What do we know? SAS: cosine rule
Plan \(36+64-96\cos70^\circ\)
Show working
- 67.17
- 8.20
Answer 8.20
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(36+64-96\cos70\) | M1 | ||
| 8.20 | A1 | ||
| Total: 2 marks | |||
Guide me
What is it asking? an angle
What do we know? SSS with BD² = 67.17
Plan \(\cos C=(25+49-67.17)/70\)
Show working
- 84.4
Answer 84.4
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(\frac{25+49-67.17}{70}\) | M1 | ||
| 84.4 | A1 | ||
| Total: 2 marks | |||
Guide me
What is it asking? an area
What do we know? 22.55 + 17.42
Plan add
Show working
- 39.97
Answer 40.0
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(\tfrac12(6)(8)\sin70+\tfrac12(5)(7)\sin84.4\) | M2 | ||
| 40.0 | A1 | ||
| Total: 3 marks | |||
Can I do this?
- I can find the area of any triangle with ½ab sin C.
- I can work back from an area to a side or angle.
- I can split a shape and chain the rules.
Anything unticked: revise that section first. All ticked: take the quiz.
Quiz
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