Simultaneous
Simultaneous equations by elimination
In this note
- 2.5Solve two simultaneous linear equations by elimination.
- 2.5Multiply one or both equations first so a letter matches.
- 2.5Form simultaneous equations from a problem and answer in context.
Before you start: Linear equations. Next: Substitution, and a line with a curve.
Formula bank
Two equations, one pair of answers
\(x+y=10\) has endless solutions; so does \(x-y=4\). Simultaneous equations want the ONE pair \((x,y)\) that makes both true - on a graph, where the two lines cross. Adding or subtracting the equations keeps them balanced and can make one letter disappear.
General methodHow to solve by elimination
- Line the equations up (x under x, y under y, numbers on the right) and label them (1) and (2).
- Make the numbers in front of one letter the same: multiply one or both WHOLE equations.
- Same signs: subtract. Different signs: add. Solve for the letter that is left.
- Substitute that value into either original equation to find the other letter.
- Check both values in the other equation.
Example Solve \(4x+3y=10\) and \(2x-5y=18\).
Multiply (2) by 2 to get \(4x\) in both, then subtract.
- (2) × 2: \(4x-10y=36\)
- (1) − new: \(13y=-26\Rightarrow y=-2\)
- \(4x-6=10\Rightarrow x=4\)
- check (2): \(8+10=18\) ✓
Answer \(x=4,\ y=-2\)
Try it yourself
Show answer
Answer \(x=7,\ y=3\)
Show answer
Answer \(x=4,\ y=3\)
Hint
Show answer
Answer \(x=3,\ y=-1\)
Forming them from words
General methodHow to set up simultaneous equations from a problem
- Choose two letters for the two unknowns (say what each means).
- Write one equation for each fact given.
- Solve by elimination and answer the question with units.
Example 2 adult tickets and 3 child tickets cost $270. 1 adult and 2 child tickets cost $160. Find the cost of each ticket.
a = adult, c = child: two equations, then eliminate.
- \(2a+3c=270\), \(a+2c=160\)
- (2) × 2: \(2a+4c=320\)
- subtract: \(c=50\)
- \(a=160-100=60\)
Answer adult $60, child $50
Ways they test it
Type 1 Solve, showing working
"Solve \(5x-2y=19\) and \(3x+4y=1\). You must show all your working." (3 marks)
Spot it two linear equations.
- Match one letter (here: (1) × 2 gives −4y).
- Add or subtract.
- Substitute back.
For example \(10x-4y=38\) and \(3x+4y=1\)
- add: \(13x=39\Rightarrow x=3\)
- \(9+4y=1\Rightarrow y=-2\)
Answer \(x=3,\ y=-2\)
Type 2 Decimals
"Solve \(2x+3y=3.4\) and \(5x+2y=4.1\)."
Spot it decimal right-hand sides: same method.
- Match a letter.
- Work carefully with the decimals.
For example (1)×2, (2)×3: \(4x+6y=6.8\), \(15x+6y=12.3\)
- \(11x=5.5\Rightarrow x=0.5\)
Answer \(x=0.5,\ y=0.8\)
Type 3 In context
"4 cups and 5 plates weigh 105 g ... 2 cups and 3 plates weigh 59 g. Find the mass of a cup." (4 marks)
Spot it two items, two totals.
- Two letters, two equations.
- Eliminate.
- Answer the question asked.
Mistakes to avoid
- ✗ \(2(x-5y=18)\) as \(2x-10y=18\)✓ \(4x-10y=36\)Multiply EVERY term, including the right-hand side.
- ✗ \(4x+3y\) minus \(4x-10y\) = \(-7y\)✓ \(13y\)\(3y-(-10y)=13y\).
- ✗ Answers with no working✓ show each stepWorking is required for the marks.
Summary
- Match the numbers in front of one letter (multiply whole equations).
- Same signs subtract, different signs add.
- Substitute back; check in the other equation.
- The answer is one pair: where the two lines cross.
If you see …
- "show all your working"write the multiplied equations and the add/subtract step.
- two items and two totalstwo letters, two equations.
Practice
Practice: easy, medium, hard
Easy
Hint
Show answer
Answer \(x=4,\ y=2\)
Hint
Show answer
Answer \(x=3,\ y=2\)
Show answer
Answer \(x=9,\ y=3\)
Medium
Guide me
What is it asking? x and y
What do we know? × (2) by 2 gives −4y
Plan then add
Show working
- \(6x-4y=26\)
- add: \(7x=35\Rightarrow x=5\)
- \(5+4y=9\Rightarrow y=1\)
Answer \(x=5,\ y=1\)
Guide me
What is it asking? x and y
What do we know? × (1) by 2 gives −4y
Plan then add
Show working
- \(10x-4y=38\)
- \(13x=39\Rightarrow x=3\)
- \(9+4y=1\Rightarrow y=-2\)
Answer \(x=3,\ y=-2\)
Guide me
What is it asking? child ticket
What do we know? \(2a+3c=270\), \(a+2c=160\)
Plan × (2) by 2, subtract
Show working
- \(2a+4c=320\)
- \(c=50\)
Answer $50
Hard
Guide me
What is it asking? x and y
What do we know? match y: (1) × 2, (2) × 3
Plan subtract
Show working
- \(4x+6y=6.8\)
- \(15x+6y=12.3\)
- \(11x=5.5\Rightarrow x=0.5\)
- \(1+3y=3.4\Rightarrow y=0.8\)
Answer \(x=0.5,\ y=0.8\)
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| coefficients matched | M1 | ||
| one letter eliminated | M1 | ||
| \(x=0.5,\ y=0.8\) | A1 | ||
| Total: 3 marks | |||
Guide me
What is it asking? x and y
What do we know? match x: × 2 and × 3
Plan \(6x+8y=10\), \(6x-9y=27\)
Show working
- subtract: \(17y=-17\Rightarrow y=-1\)
- \(3x-4=5\Rightarrow x=3\)
Answer \(x=3,\ y=-1\)
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(6x+8y=10\) and \(6x-9y=27\) | M1 | ||
| \(17y=-17\) | M1 | ||
| x = 3, y = −1 | A1 | ||
| Total: 3 marks | |||
Guide me
What is it asking? a cup
What do we know? \(4c+5p=105\), \(2c+3p=59\)
Plan × (2) by 2, subtract
Show working
- \(4c+6p=118\)
- subtract: \(p=13\)
- \(2c+39=59\Rightarrow c=10\)
Answer 10 g
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| both equations | B1 | ||
| elimination | M1 | ||
| p = 13 | A1 | ||
| c = 10 g | A1 | ||
| Total: 4 marks | |||
Can I do this?
- I can solve simultaneous equations by elimination.
- I can multiply one or both equations to match a letter.
- I can form and solve simultaneous equations from a problem.
Anything unticked: revise that section first. All ticked: take the quiz.
Quiz
The multiple-choice and guided questions need JavaScript. The concept checks and exam practice below work without it.
Your progress on this note is saved when JavaScript is on.