Trigonometric Graphs
Solving trigonometric equations
In this note
- E6.4Solve \(\sin x=k\), \(\cos x=k\) and \(\tan x=k\) for \(0^\circ\le x\le360^\circ\), giving every solution.
- E6.4Rearrange first, e.g. \(2\cos x+1=0\).
- E6.4Handle negative values and spot equations with no solutions.
Before you start: Graphs of sin, cos and tan and rearranging.
Formula bank
Solving a trig equation
The calculator gives one angle. The graph shows there is usually a second one between 0° and 360°, found with the symmetry rule.
General methodHow to solve any trig equation for 0° to 360°
- Rearrange to \(\sin x=k\), \(\cos x=k\) or \(\tan x=k\).
- For sin or cos: if k is above 1 or below −1, there are no solutions.
- Calculator: \(x=\sin^{-1}k\) (or \(\cos^{-1}k\), \(\tan^{-1}k\)).
- Second angle: sin → 180° − first; cos → 360° − first; tan → first + 180°.
- If an angle is negative, add 360° (or 180° for tan) to bring it into range. Give answers to 1 d.p.
\(2\cos x+1=0\Rightarrow\cos x=-\tfrac12\). Calculator: 120°. Second: 360° − 120° = 240°.
Example Solve \(4\cos x+1=0\) for \(0^\circ\le x\le360^\circ\).
Rearrange, calculator, then 360° − first.
- \(\cos x=-0.25\)
- \(x=\cos^{-1}(-0.25)=104.48\ldots\)
- second: \(360-104.48=255.52\)
Answer 104.5° or 255.5°
Try it yourself
Show answer
Answer 17.5, 162.5
Show answer
Answer 68.2, 248.2
Negative values and no solutions
Example Solve \(3\sin x+1=0\).
\(\sin x=-\tfrac13\); the calculator gives a negative angle, so move it into range.
- \(\sin^{-1}(-\tfrac13)=-19.47^\circ\)
- \(-19.47+360=340.5^\circ\)
- second: \(180-(-19.47)=199.5^\circ\)
Answer 199.5° or 340.5°
\(2\sin x=3\) gives \(\sin x=1.5\): impossible, so there are no solutions.
Try it yourself
Show answer
Answer 135, 315
Show answer
Answer 0
Ways they test it
Type 1 Rearrange and solve
"Solve \(2\cos x+1=0\) for \(0^\circ\le x\le360^\circ\)." (3 marks)
Spot it a trig function with numbers around it.
- cos x = −½.
- 120°.
- 360° − 120° = 240°.
Type 2 After a sketch
"(a) Sketch \(y=\sin x\). (b) Solve \(5\sin x-2=0\)." (2 + 3 marks)
Spot it a sketch in part (a).
- sin x = 0.4.
- 23.6° and 180° − 23.6°.
For example \(\sin x=0.4\)
Answer 23.6°, 156.4°
Type 3 Exact values
"Solve \(2\sin x-\sqrt3=0\)." (non-calculator)
Spot it a surd: an exact value.
- \(\sin x=\tfrac{\sqrt3}2\) → 60°.
- 180° − 60° = 120°.
For example \(\sin x=\tfrac{\sqrt3}2\)
Answer 60°, 120°
Type 4 A condition
"\(\cos x=\tfrac12\) and x is reflex. Find x." (1 mark)
Spot it 'reflex', 'obtuse', 'acute'.
- Find both angles.
- Keep the one that fits.
For example 60° and 300°
Answer 300°
Mistakes to avoid
- ✗ Only the calculator answer✓ both solutionsThe graph crosses twice.
- ✗ cos: 180° − x✓ cos: 360° − xThat is the sin rule.
- ✗ Giving −19.5°✓ move it into 0°-360°Out of range.
- ✗ sin x = 1.5 → 'I'm wrong'✓ no solutionsA valid answer.
Summary
- Rearrange to sin x, cos x or tan x = k.
- Calculator first angle; second from the symmetry rule.
- Negative angles: add 360° (tan: 180°).
- |k| > 1 for sin or cos: no solutions.
If you see …
- "for 0° ≤ x ≤ 360°"expect two answers.
- "reflex" / "obtuse"choose the answer in that range.
Practice
Practice: easy, medium, hard
Easy
Show answer
Answer 120, 240
Show answer
Answer 23.6, 156.4
Show answer
Answer 300
Medium
Guide me
What is it asking? two angles
What do we know? cos x = −0.25
Plan 360° − first
Show working
- \(\cos^{-1}(-0.25)=104.5\)
- 360 − 104.5 = 255.5
Answer 104.5, 255.5
Guide me
What is it asking? two angles
What do we know? sin x = −1/3: calculator −19.47°
Plan 180° + 19.47°, 360° − 19.47°
Show working
- 199.5° and 340.5°
Answer 199.5, 340.5
Guide me
What is it asking? two angles
What do we know? \(\sin^{-1}\tfrac23\)
Plan 180° − first
Show working
- 41.8° and 138.2°
Answer 41.8, 138.2
Hard
Guide me
What is it asking? two angles
What do we know? sin x = 0.4
Plan 180° − first
Show working
- \(\sin x=0.4\)
- 23.6° and 156.4°
Answer 23.6, 156.4
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| sin x = 0.4 | M1 | ||
| 23.6 | B1 | ||
| 156.4 | B1 | ||
| Total: 3 marks | |||
Guide me
What is it asking? two angles
What do we know? \(\sin x=\tfrac{\sqrt3}2\)
Plan exact value 60°
Show working
- 60° and 180° − 60° = 120°
Answer 60, 120
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| 60 | B1 | ||
| 120 | B1 | ||
| Total: 2 marks | |||
Guide me
What is it asking? two angles
What do we know? cos x = −0.75
Plan 360° − first
Show working
- \(\cos^{-1}(-0.75)=138.6\)
- 360 − 138.6 = 221.4
Answer 138.6, 221.4
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| cos x = −0.75 | M1 | ||
| 138.6 | B1 | ||
| 221.4 | B1 | ||
| Total: 3 marks | |||
Can I do this?
- I can solve sin x = k, cos x = k and tan x = k for 0° ≤ x ≤ 360°.
- I can deal with negative values and spot equations with no solutions.
- I can use exact values and conditions like 'reflex'.
Anything unticked: revise that section first. All ticked: take the quiz.
Quiz
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