Algebra
The quadratic formula
In this note
- 2.5Solve \(ax^{2}+bx+c=0\) with the quadratic formula, giving answers to 2 d.p. or 3 s.f.
- 2.5Give exact answers like \(3\pm\sqrt5\).
- 2.5Rearrange first and use the signs of a, b and c correctly.
Before you start: Completing the square (the formula comes from it). When it factorises, factorising is quicker: Solving by factorising.
Formula bank
Using the formula
The formula solves ANY quadratic. It is completing the square done once with letters. If the number under the square root, \(b^{2}-4ac\), is negative, the equation has no solutions.
General methodHow to use the quadratic formula
- Rearrange to \(ax^{2}+bx+c=0\).
- Write down a, b and c WITH their signs.
- Work out \(b^{2}-4ac\) first (use brackets: \((-3)^{2}=9\)).
- Put it into \(x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}\) and work out the + answer and the − answer.
- Round only at the end, to the accuracy asked.
Example Solve \(2x^{2}+5x-4=0\), giving your answers to 2 decimal places.
\(a=2,\ b=5,\ c=-4\).
- \(b^{2}-4ac=25+32=57\)
- \(x=\dfrac{-5\pm\sqrt{57}}4\)
- \(x=\dfrac{-5+7.550}4=0.638\) or \(x=\dfrac{-5-7.550}4=-3.138\)
Answer 0.64 or −3.14
Example 2 Solve \(x^{2}-6x+4=0\), giving exact answers.
\(a=1,\ b=-6,\ c=4\), so \(-b=6\).
- \(b^{2}-4ac=36-16=20\)
- \(x=\dfrac{6\pm\sqrt{20}}2=\dfrac{6\pm2\sqrt5}2\)
Answer \(3\pm\sqrt5\)
Try it yourself
Show answer
Answer 57
Show answer
Answer 1.19, −4.19
Show answer
Answer 0.81, −0.31
Ways they test it
Type 1 Answers to 2 d.p.
"Solve \(2x^{2}-3x-6=0\). Show all your working and give your answers correct to 2 decimal places." (4 marks)
Spot it '2 decimal places' or '3 significant figures'.
- a, b, c with signs.
- Formula with brackets.
- Both answers, rounded at the end.
For example \(x=\dfrac{3\pm\sqrt{57}}4\)
Answer 2.64, −1.14
Type 2 Rearrange first
"Solve \(5x^{2}=3x+1\)."
Spot it not '= 0' yet.
- Move everything left: \(5x^{2}-3x-1=0\).
- Then the formula.
For example \(x=\dfrac{3\pm\sqrt{29}}{10}\)
Answer 0.84, −0.24
Type 3 Exact answers
"Solve \(x^{2}-4x-1=0\), giving your answers in the form \(p\pm\sqrt q\)." (non-calculator)
Spot it 'exact' or 'surd form'.
- Formula.
- Simplify the surd, divide every term by 2a.
For example \(x=\dfrac{4\pm\sqrt{20}}2\)
- \(=\dfrac{4\pm2\sqrt5}2\)
Answer \(2\pm\sqrt5\)
Type 4 The last step of a bigger question
"Show that ... = 0. Solve ... giving answers to 2 d.p." (a problem or a fraction equation)
Spot it after forming an equation.
- Use the given quadratic even if you couldn't 'show' it.
Mistakes to avoid
- ✗ \(b=-3\): \(b^{2}=-9\)✓ \((-3)^{2}=9\)Square with brackets.
- ✗ \(b=-6\): \(-b=-6\)✓ \(-b=+6\)Minus a negative is positive.
- ✗ \(-b\pm\dfrac{\sqrt{b^{2}-4ac}}{2a}\)✓ \(\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}\)Divide the WHOLE top by 2a.
- ✗ Rounding before the end✓ keep full calculator valuesEarly rounding changes the 2nd decimal place.
Summary
- \(x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}\) for \(ax^{2}+bx+c=0\).
- a, b, c with their signs; brackets when substituting.
- Two answers: one with +, one with −.
- \(b^{2}-4ac<0\): no solutions.
If you see …
- "give your answers to 2 decimal places"the quadratic formula.
- "exact" / "surd form"formula, then simplify the surd.
Practice
Practice: easy, medium, hard
Easy
Show answer
Answer −0.46, −6.54
Show answer
Answer 0.43, −0.77
Hint
Show answer
Answer none
Medium
Guide me
What is it asking? x to 2 d.p.
What do we know? \(a=2,\ b=-3,\ c=-6\)
Plan \(b^{2}-4ac=57\)
Show working
- \(x=\dfrac{3\pm\sqrt{57}}4\)
- 2.637…, −1.137…
Answer 2.64, −1.14
Guide me
What is it asking? x to 2 d.p.
What do we know? rearrange first
Plan \(5x^{2}-3x-1=0\)
Show working
- \(x=\dfrac{3\pm\sqrt{29}}{10}\)
Answer 0.84, −0.24
Guide me
What is it asking? x to 2 d.p.
What do we know? \(a=3,\ b=-2,\ c=-7\)
Plan \(4+84=88\)
Show working
- \(x=\dfrac{2\pm\sqrt{88}}6\)
Answer 1.90, −1.23
Hard
Guide me
What is it asking? exact x
What do we know? \(b^{2}-4ac=20\)
Plan \(\sqrt{20}=2\sqrt5\), divide by 2
Show working
- \(x=\dfrac{4\pm\sqrt{20}}2\)
- \(=2\pm\sqrt5\)
Answer \(2\pm\sqrt5\)
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(\dfrac{4\pm\sqrt{20}}2\) | M1 | ||
| \(2\pm\sqrt5\) | A1 | ||
| Total: 2 marks | |||
Guide me
What is it asking? x to 2 d.p.
What do we know? \(b^{2}-4ac=1+40\)
Plan \(\sqrt{41}\)
Show working
- \(x=\dfrac{-1\pm\sqrt{41}}4\)
Answer 1.35, −1.85
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(\sqrt{41}\) | B1 | ||
| \(\dfrac{-1\pm\sqrt{41}}4\) | M1 | ||
| 1.35, −1.85 | A1A1 | ||
| Total: 4 marks | |||
Guide me
What is it asking? x to 2 d.p.
What do we know? expand and rearrange
Plan \(x^{2}+7x-1=0\)
Show working
- \(x^{2}+5x=1-2x\)
- \(x^{2}+7x-1=0\)
- \(x=\dfrac{-7\pm\sqrt{53}}2\)
Answer −0.14, −7.14
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(x^{2}+7x-1=0\) | M1 | ||
| \(\dfrac{-7\pm\sqrt{53}}2\) | M1 | ||
| −0.14, −7.14 | A1A1 | ||
| Total: 4 marks | |||
Can I do this?
- I can use the quadratic formula with the correct signs.
- I can give answers to 2 d.p. or in exact surd form.
- I can rearrange into the standard form first.
Anything unticked: revise that section first. All ticked: take the quiz.
Quiz
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