Circles
Parts of a circle and the right-angle theorems
In this note
- 4.1Use the words radius, diameter, chord, tangent, arc, sector and segment.
- 4.7Use: the angle in a semicircle is 90°.
- 4.7Use: the angle between a tangent and a radius is 90°, with triangle facts and Pythagoras.
Before you start: Angle facts. Next: More circle theorems.
Formula bank
Parts of a circle
| Word | Meaning |
|---|---|
| radius | centre to the circle |
| diameter | chord through the centre (2 × radius) |
| chord | straight line joining two points on the circle |
| tangent | straight line touching the circle at one point |
| arc | part of the circumference |
| sector | region between two radii and an arc |
| segment | region between a chord and an arc |
Try it yourself
Show answer
Answer sector
Show answer
Answer chord
Two right angles
General methodHow to use the two right-angle theorems
- Look for a DIAMETER with a third point on the circle: that corner is 90° (angle in a semicircle).
- Look for a TANGENT: the radius to the touching point meets it at 90°.
- Mark the right angle, then use angles in a triangle (180°) or Pythagoras.
- Look for two radii from the centre: an isosceles triangle.
Example PT is a tangent at T to a circle centre O. OT = 5 cm, PT = 12 cm. Find OP.
Right angle at T, so Pythagoras.
- \(OP^{2}=5^{2}+12^{2}=169\)
Answer OP = 13 cm
Try it yourself
Show answer
Answer 49
Show answer
Answer 10
Ways they test it
Type 1 Name the parts
"Complete the labels: chord, tangent, sector, segment." (2 marks)
Spot it a labelled diagram.
- Line or region?
- Two radii = sector; chord = segment.
Type 2 Angle in a semicircle
"AB is a diameter. Angle CAB = 34°. Find angle ABC, giving a reason." (2 marks)
Spot it a diameter and a triangle.
- Angle ACB = 90° (angle in a semicircle).
- 180 − 90 − 34.
For example angle ACB = 90°
Answer 56°
Type 3 Tangent + Pythagoras or trig
"PT is a tangent. OT = 7 cm, angle OPT = 24°. Find OP." (3 marks)
Spot it a tangent and a length.
- Right angle at T.
- Pythagoras or SOHCAHTOA.
For example \(\sin24^\circ=\dfrac7{OP}\)
Answer 17.2 cm
Mistakes to avoid
- ✗ Sector and segment swapped✓ sector: two radii; segment: a chordLearn the pictures.
- ✗ Right angle at the centre✓ right angle at the circumferenceSemicircle theorem.
- ✗ Missing the tangent right angle✓ OT ⟂ tangentIt is usually not marked.
Summary
- Sector: between two radii. Segment: between a chord and an arc.
- Angle in a semicircle = 90°.
- Tangent ⟂ radius at the point of contact.
- Two radii → isosceles triangle.
If you see …
- a diameter in a trianglethe angle opposite it is 90°.
- a tangentdraw the radius: right angle.
Practice
Practice: easy, medium, hard
Easy
Show answer
Answer segment
Show answer
Answer 56
Show answer
Answer 13
Medium
Guide me
What is it asking? an angle
What do we know? angle ABC = 63° (semicircle)
Plan OB = OC: isosceles
Show working
- angle OCB = 63°
- angle BOC = 180 − 126 = 54°
Answer 54
Guide me
What is it asking? a length
What do we know? right angle at T
Plan \(17^{2}-8^{2}\)
Show working
- \(\sqrt{225}=15\)
Answer 15
Guide me
What is it asking? an angle
What do we know? angle OTP = 90°
Plan 180 − 90 − 58
Show working
- 32°
Answer 32
Hard
Guide me
What is it asking? a length
What do we know? right angle at T
Plan \(\sin24^\circ=\tfrac7{OP}\)
Show working
- \(OP=7\div\sin24^\circ=17.2\)
Answer 17.2
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| 90° at T | B1 | ||
| \(\sin24^\circ=\tfrac7{OP}\) | M1 | ||
| 17.2 | A1 | ||
| Total: 3 marks | |||
Guide me
What is it asking? an angle
What do we know? right angle at T
Plan \(\tan TOP=\tfrac{12}5\)
Show working
- \(\tan^{-1}2.4=67.4^\circ\)
Answer 67.4
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| \(\tan^{-1}\tfrac{12}5\) | M1 | ||
| 67.4 | A1 | ||
| Total: 2 marks | |||
Guide me
What is it asking? a radius
What do we know? angle ACB = 90°
Plan AB by Pythagoras, then halve
Show working
- \(AB=\sqrt{36+64}=10\)
- radius 5
Answer 5
| Part | Answer / working | Marks | Guidance |
|---|---|---|---|
| AB = 10 | M1 | ||
| 5 | A1 | ||
| Total: 2 marks | |||
Can I do this?
- I know the names of the parts of a circle.
- I can use the angle in a semicircle.
- I can use tangent ⟂ radius with angles and Pythagoras.
Anything unticked: revise that section first. All ticked: take the quiz.
Quiz
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