Energy, work & power

Power

Power Core 2 min read

Power

Power is the rate at which energy is transferred (or work is done). \[ P = \frac{W}{t} = \frac{E}{t} \]
SymbolQuantityUnit
\( P \)Powerwatt, W
\( W \)Work done (energy transferred)joule, J
\( E \)Energy transferredjoule, J
\( t \)Time takensecond, s
1 watt = 1 joule per second (1 W = 1 J/s). A more powerful machine transfers the same energy in a shorter time.
Common power units:
  • 1 kW (kilowatt) = 1000 W
  • 1 MW (megawatt) = 1 000 000 W
  • Typical human walking: ~100 W
  • Typical car engine: ~60–120 kW
  • Large power station: ~1–3 GW

Power and velocity (Extended)

Extended (Supplement)
When a constant force \( F \) moves an object at constant velocity \( v \): \[ P = Fv \] Derived from: \( P = W/t = Fd/t = F \times (d/t) = Fv \).

This is useful when the force and speed are known but time and distance are not.

Worked examples

Example 1 — calculate power

A motor transfers 15 000 J of energy in 25 s. Calculate the power of the motor.

\( P = \dfrac{E}{t} = \dfrac{15\,000}{25} = 600\,\text{W} \)

Example 2 — find time from power and energy

A 2.0 kW electric kettle transfers 360 000 J of thermal energy. How long does it take?

\( t = \dfrac{E}{P} = \dfrac{360\,000}{2000} = 180\,\text{s} = 3.0\,\text{min} \)

Example 3 — stair-climbing power

A student of mass 60 kg climbs stairs of vertical height 4.0 m in 6.0 s. Calculate the power output. (g = 10 N/kg)

Work done against gravity: \( W = mgh = 60 \times 10 \times 4.0 = 2400\,\text{J} \)

\( P = \dfrac{W}{t} = \dfrac{2400}{6.0} = 400\,\text{W} \)

Example 4 — P = Fv (Extended)

A car's engine exerts a driving force of 2500 N when travelling at a constant speed of 30 m/s. Calculate the power output of the engine.

\( P = Fv = 2500 \times 30 = 75\,000\,\text{W} = 75\,\text{kW} \)

Note: at constant speed, driving force = friction + air resistance, so all power goes to overcoming drag.

The stair-climbing experiment is a classic IGCSE practical: measure mass, height, and time. Always note that the calculated power is the minimum — it ignores the energy used to swing the legs. In "P = Fv" questions, check whether the object is at constant velocity; if it is accelerating, the net force is non-zero and the power equation is more complex.