Physical quantities & measurement
Measuring length and volume
Instruments and units
In physics, every measurement must include a number and a unit. The International System of Units (SI) is used throughout Cambridge IGCSE Physics.
| Unit | Symbol | Relation to metre |
|---|---|---|
| kilometre | km | 1 km = 1000 m |
| centimetre | cm | 100 cm = 1 m |
| millimetre | mm | 1000 mm = 1 m |
Using a ruler
A metre rule (or shorter 30 cm rule) is used to measure length directly.
- Place the zero mark of the rule exactly at one end of the object.
- Read the scale at the other end of the object.
- Keep your eye directly above the mark (not to the side).
Vernier callipers and micrometers
For smaller lengths, more precise instruments are used.
| Instrument | Range | Precision | Use |
|---|---|---|---|
| Ruler | 0–1 m | ±1 mm | General lengths |
| Vernier callipers | 0–150 mm | ±0.1 mm | External/internal widths, depths |
| Micrometer screw gauge | 0–25 mm | ±0.01 mm | Wire diameter, paper thickness |
Measuring volume
Regular shapes
For objects with a regular shape, volume is calculated from length measurements:
- Cube: \( V = l^3 \)
- Cuboid: \( V = l \times w \times h \)
- Cylinder: \( V = \pi r^2 h \)
- Sphere: \( V = \tfrac{4}{3}\pi r^3 \)
Measuring cylinder
A measuring cylinder (graduated cylinder) is used to measure the volume of a liquid directly. It has a scale marked in cm³.
- Place the cylinder on a flat, level surface.
- Lower your eye to the level of the liquid surface.
- Read the bottom of the meniscus (the curved surface of the water).
Volume by displacement
An irregular solid that does not dissolve in water can be measured using the displacement method.
- Part-fill a measuring cylinder with water. Record the initial volume \( V_1 \).
- Carefully lower the solid into the water using a thread.
- Record the new volume \( V_2 \).
- Volume of solid = \( V_2 - V_1 \)
Worked example — volume by displacement
A stone is lowered into a measuring cylinder containing 30 cm³ of water. The water level rises to 42 cm³. Calculate the volume of the stone.
Solution:
\( V_{\text{stone}} = V_2 - V_1 = 42 - 30 = 12 \text{ cm}^3 \)
Notice: the answer has the same unit as the scale on the measuring cylinder (cm³).