Physical quantities & measurement
Resultant of two vectors
The resultant of two vectors
At IGCSE Extended, you only need to find the resultant of two vectors that act at right angles to each other (perpendicular). This is done either by calculation or by a scale drawing.
Vectors at right angles — Pythagoras and trigonometry
When two vectors are perpendicular, they form the two shorter sides of a right-angled triangle. The resultant is the hypotenuse.
- Draw a rough sketch showing the two vectors at 90° to each other (tip-to-tail).
- Apply Pythagoras: \( R = \sqrt{a^2 + b^2} \)
- Find the angle: \( \theta = \arctan\!\left(\dfrac{b}{a}\right) \) — the angle between the resultant and the larger vector.
- State the resultant as: magnitude + angle from a reference direction.
Worked example — two forces at right angles
A boat experiences a force of 30 N due east from its engine and a current force of 40 N due north. Find the resultant force (magnitude and direction).
Step 1 — Magnitude:
\( R = \sqrt{30^2 + 40^2} = \sqrt{900 + 1600} = \sqrt{2500} = 50 \text{ N} \)
Step 2 — Direction:
\( \theta = \arctan\!\left(\dfrac{40}{30}\right) = \arctan(1.33) \approx 53° \text{ from east} \) (i.e. N 53° E, or 53° north of east)
Answer: The resultant force is 50 N at 53° north of east.
Graphical method — scale drawing
An alternative to calculation: draw the vectors to scale, tip-to-tail, and measure the resultant directly.
- Choose a suitable scale (e.g. 1 cm : 10 N).
- Draw the first vector as an arrow to scale in the correct direction.
- From the tip of the first vector, draw the second vector to scale in its direction.
- Draw the resultant arrow from the tail of the first vector to the tip of the second.
- Measure the length of the resultant arrow and convert using the scale. Measure the angle with a protractor.
Resultant of two velocities
The same method applies to velocity vectors. A classic scenario is a boat crossing a river.
Worked example — river crossing
A swimmer can swim at 2 m/s perpendicular to a riverbank. The river current flows at 1.5 m/s parallel to the bank. Find the resultant velocity of the swimmer.
\( R = \sqrt{2^2 + 1.5^2} = \sqrt{4 + 2.25} = \sqrt{6.25} = 2.5 \text{ m/s} \)
\( \theta = \arctan\!\left(\dfrac{1.5}{2}\right) = \arctan(0.75) \approx 37° \) from the direction of swimming (i.e. angled 37° downstream).
Answer: Resultant velocity = 2.5 m/s at 37° downstream from the perpendicular to the bank.
Equilibrium and zero resultant
If two equal and opposite forces act on an object, their resultant is zero — the object is in equilibrium (no net force, so no acceleration). Equilibrium is explored further in the Forces chapter.