Physical quantities & measurement
Measuring multiples and averages
Why measure multiples?
When an individual measurement is very small or difficult to time precisely, measuring a large number of identical events and then dividing gives a much more accurate result for a single event.
\[ \text{Value of one} = \frac{\text{Total measurement}}{n} \] where \( n \) is the number of repetitions.
Common applications
Measuring the period of a pendulum
This is the most common IGCSE exam example. The procedure was covered in the previous subtopic. The key idea is:
- Measure the time for 20 (or more) complete oscillations.
- \( T = \dfrac{\text{total time}}{20} \) — this averages out reaction time errors across 20 attempts.
- Repeat the timing at least three times and find the mean, then divide by 20.
Measuring the diameter of a thin wire
A single turn of wire is too thin to measure reliably with a ruler. Winding many turns into a tight coil and measuring the total length of the coil is more precise.
- Wind the wire tightly in closely packed turns around a pencil (so coils do not overlap).
- Count the number of turns \( n \) carefully.
- Measure the total length \( L \) of the coil with a ruler.
- Diameter of wire: \( d = \dfrac{L}{n} \)
Worked example — wire diameter
40 turns of a copper wire are wound tightly on a pencil. The total length of the coil is 24 mm. Calculate the diameter of the wire.
\( d = \dfrac{24}{40} = 0.60 \text{ mm} \)
Converting: 0.60 mm = 6.0 × 10−4 m
Measuring the thickness of a sheet of paper
Similarly, a single sheet is too thin to measure accurately with a ruler.
- Stack exactly 100 sheets of paper (count carefully).
- Measure the total thickness of the stack with a ruler.
- Thickness of one sheet = total ÷ 100
Taking the mean — reducing random error
Repeating any measurement multiple times and averaging removes random errors. A random error is one that varies unpredictably from one reading to the next (e.g. reaction time, parallax from a slightly different angle each time).
Worked example — mean value of reaction time
A student measures the time for 20 oscillations of a pendulum three times: 31.8 s, 32.2 s, 32.0 s. Find the period.
Mean time for 20 oscillations: \( \bar{t} = \dfrac{31.8 + 32.2 + 32.0}{3} = \dfrac{96.0}{3} = 32.0 \text{ s} \)
Period: \( T = \dfrac{32.0}{20} = 1.60 \text{ s} \)